An aircraft flew a distance of from Amsterdam to Cairo at an average speed of 820 km/h and returned non-stop by the same route at an average speed of 656 km/h. Given that the aircraft took 1 hour more for the return trip, calculate x

Answer:[tex]x=3280[/tex]Step-by-step explanation:Given that the distance from Amsterdam to Cairo is x.It is given that first the aircraft flows with an average speed of 820 km/h.Time taken to reach Cairo would be[tex]t1=\frac{x}{820}[/tex]Without stop the aircraft would return back withan average speed of 656 km/h.Time taken for this is ,[tex]t2=\frac{x}{656}[/tex]Now its given that t2 is 1 hour more than t1.t2=t1+1,[tex]\frac{x}{656}=\frac{x}{820}+1[/tex][tex]\frac{x*820}{656} =x+820[/tex][tex]x=3280[/tex]